9.1 Examples and basic properties

Let us see some examples. Trivial designs are single block consisting of all points or all k-subsets of 𝒫. These are often not focus of study in designs.

As a first non-trivial example, a symmetric Steiner system S⁢(2,2,3) can be easily represented as triangle on 3 points with the lines denoting the blocks.

Example 9.1 (Fano plane ).

This is simply the symmetric Steiner system S⁢(2,3,7). More geometrically,

Alternatively, set 𝒫=ℤ7 and ℬ={(x,x+1,x+3):x∈ℤ7}.

More generally, symmetric Steiner systems S⁢(2,q+1,q2+q+1) are called as projective planes and we shall see more about them later. Why k=q implies that v=q2+q+1 follows from the below exercise which is via double counting of pairs of t-sets and blocks containing them.

Exercise 9.2.

Show that in a t−(v,k,λ) design b=λ⁢(vt)/(kt).

Example 9.3.

Let 𝒫=𝔽24∖{0} and ℬ={(x,y,z):x+y+z=0}. Clearly v=15,k=3. Take x≠y∈𝒫. Then clearly there exists a unique z∈𝒫 such that x+yz=0. Thus, any pair of points belongs to exactly one block i.e., this is a S⁢(2,3,15).

A second Steiner system on 𝒫=𝔽24 is as follows : ℬ={(w,x,y,z):w+x+y+z=0}. This is a S⁢(3,4,16). If we take blocks containing 0 and delete 0, we get S⁢(2,3,15), the previous Steiner system.

Exercise(A) 9.4.

Take the edges of K6 as points. Let the blocks be sets of 3 edges that either are the edges of a perfect matching or the edges of a triangle. Show that this is S⁢(2,3,15). Is it isomorphic to the design in the above example ?

One of the first properties of designs is regularity as sets i.e., every point belongs to the same number of sets, say r. r is called as replication number.

Lemma 9.5.

Let ℬ be a (v,k,λ) design containing b blocks. Then every point is contained in exactly r blocks where r satisfies

r⁢(k−1)=λ⁢(v−1);b⁢k=v⁢r.
Proof.

We will prove by double counting. Let p∈𝒫 and suppose its replication number is rp. Let us count the cardinality of the set {(x,B):B∈ℬ,p,x∈B,p≠x}.

For the v−1 points x≠p, there are exactly λ blocks containing both x,p. This gives the cardinality to be λ⁢(v−1).

On the other hand, there are rp blocks B containing p and each of the blocks contains k−1 other points. So the cardinality rp⁢(k−1). Thus we have rp⁢(k−1)=λ⁢(v−1). This gives that rp is independent of p. Now the second identity follows by double counting the set {(p,B):B∈ℬ,p∈B}. ∎

In other words, the above shows that a (v,k,λ) design is also a 1−(v,k,r) design. More generally, we have the following.

Lemma 9.6.

Let ℬ be a t−(v,k,λ) design and let 0≤i≤t. Then it is also a i−(v,k,λi) design for

λi=λ⁢(v−it−i)/(k−it−i)
Proof.

Fix an i-set I. Count the number of pairs (T,B) such that T is a t-set containing I and T⊂B∈ℬ. Summing over T gives that λ⁢(v−it−i) and summing over B gives that λi⁢(k−it−i). ∎

Exercise(A) 9.7.

Let 0≤j≤t and J is a j-subset of 𝒫. The number of blocks of an t−(v,k,λ) design that contain none of the points of J is

bj=λ⁢(v−jk)(v−tk−t).
Exercise(A) 9.8.

Let ℬ be a (v,k,λ) design with b blocks and replication number r. Prove that the complement ℬc:={𝒫∖B:B∈ℬ} is a design if b−2⁢r+λ>0. Determine the parameters.