11.3 Some bounds on chromatic number.

We shall now derive some more bounds for chromatic number. See [Sudakov 2019, Chapters 7 and 8] for more results on graph colouring and also some interesting applications. We give some simple bounds here. Some will be proved and some are left as exercises.

Lemma 11.8.
  1. 1.

    χ(G)|V(G)|α(G) where recall that α(G) is the independence number.

  2. 2.

    For any UV, χ(G)χ(G[U])+χ(G[VU]) (2χ(G)) where G[U] is the induced subgraph on U.

  3. 3.

    If G=G1G2 with V(Gi)=V(G),i=1,2 then χ(G)χ(G1)χ(G2).

  4. 4.

    χ(G)χ(G¯)|V|.

Proof.
  • (1)

    Let f be a k-colouring where k=χ(G). Hence, V(G)=f1(1)f1(2)f1(k). If vi,vjf1(m) for some m then vivj. Hence, f1(m) are independent sets. |f1(m)|α(G). Also, f1(m)f1(n)=,mn.

    |V(G)|=i=1k|f1(i)|kα(G)
  • (2)

    We can colour U using χ(G[U]) colours and now choose another χ(G[VU]) colours to colour VU. Thus G has been coloured using χ(G[U])+χ(G[VU]) colours.

  • (3)

    If ci are colourings of Gi, define c=(c1,c2). Note that if uv then (u,v)Gi for some i and for that i, ci(u)ci(v). Thus c(u)c(v) and so c is a colouring of G.

  • (4)

    Follows from (3) as GG¯=K|V|, complete graph on V.

Our argument to show that χΔ+1 can be refined to give a greedy way to colour a graph and yielding an improved bound as follows. Call a graph k-degenerate if every subgraph has a vertex of degree at most k.

Exercise(A) 11.9.

Show that G is k-degenerate iff there is an ordering of vertices v1,,vn such that each vi has at most k neighbours among v1,,vi1.

Exercise(A) 11.10.

Show that a k-degenerate graph is (k+1)-colourable. In particular, if d(G) is the minimum k such that G is k-degenerate then χ(G)d(G)+1.

Exercise 11.11.

Show that d(G)Δ(G) and find examples where d(G) is small and Δ(G) is large